Answer to Question #270238 in General Chemistry for isha

Question

What is the value of K_c for the equilibrium below at 300 K?

$$

1

2

​A2

​(g)+1

2

​B2

​(g)AB(g)

Answer 1

A₂(g)+B₂(g) ↔ 2AB(g)    k_c = 3.65

1/2A2(g)+1/2B2(g↔AB(g)    k_c1 = ?

The values in the equilibrium equation are halved so the new equilibrium constant is the square root of the previous value;

k_c1 = (k_c)^1/2 = (3.65)^1/2 = 1.91