Question

based on the following reaction cl2+Naclo=NaCL+CLO2 (not balanced)

2.5 MOCL2 measured at 20 c and 4.12 atm is reacted with 800 mL of 3.30 M NaCLO F 51.8 g of ClO2 is obtained .what is the percent yield Of the reaction ,determine the limiting and remaining (as gram) reagent

Answer 1

Cl₂ + 4NaClO → 4NaCl + 2ClO₂

Mole ratio is 1 : 4

The limiting reagent is Chlorine $Cl_2$

Moles of $NaClO={3.30}×{0.8}=2.64moles$

Moles of chlorine $=\frac{2.64}{4}=0.66moles$

Mass of chlorine $=0.66×35=23.1grams$