using the chemical equation: 3H2+N2->2NH3 determine the mole of H2 needed to form 124 grams of NH3
Molar mass of NH3 is 17.031 g/mol
Moles of "NH_3=\\frac{124}{17.031}=7.28moles"
Moles of "H_2=\\frac{3}{2}\u00d77.28=10.92moles"
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