Answer to Question #268559 in General Chemistry for grizz

Question

How many moles of nitrogen gas would be produced if 7.83 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction?

2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

Answer 1

Moles of N₂ produced can be calculated from the mole ratio of CuO : N₂ which is 3:1 from the equation given

Since moles of CuO is 7.83mol and mole ratio is 3:1

Then moles of N₂ $=1/3 (7.83)mol =2.62 mol$ of N₂ produced