Question

How many moles of nitrogen gas would be produced if 7.83 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction?

2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

Answer 1

Moles of N₂ produced can be calculated from the mole ratio of CuO : N₂ which is 3:1 from the equation given

Since moles of CuO is 7.83mol and mole ratio is 3:1

Then moles of N₂ $=1/3 (7.83)mol =2.62 mol$ of N₂ produced