Answer to Question #267812 in General Chemistry for jepoy

Question

In the production of copper from ore containing copper(II) sulfide, the ore is first roasted to change it to the oxide according to the following equation:

2CuS + 3O₂ → 2CuO + 2SO₂

Molar Masses:

• CuS (95.611 g/mol)
• O₂ (31.9988 g/mol)
• CuO (79.545 g/mol)
• SO₂ (64.0638 g/mol)

If 730 g of CuS and 379 g of O₂ are available, which reactant is limiting? What mass of CuO will be produced?

• Limiting reactant: Answer
  
• CuS
• O2
• Mass CuO: 
• Answer for part 1 and coordinate 2
  
•  g CuO

What mass of CuO can be formed from the reaction of 12.9 g of CuS and 83.4 g of O₂?

• Limiting reactant: Answer
  
• CuS
• O2
• Mass CuO: 
• Answer for part 2 and coordinate 2
  
•  g CuO

Answer 1

730/95.611= 7.77moles

379/31.9988=9.48moles

Hence CuS is the limiting reactant