Answer to Question #267750 in General Chemistry for Six

Question

What are E°

cell and ΔG° of a redox reaction at 25°C for

which n = 1 and K = 5.0×10−6?

Answer 1

∆Gº = -RT ln K

R = 8.314 J/Kmol

T = 25 + 273 = 298K

K = 5x10^-6

∆Gº = -(8.314)(298)(11.1)

∆Gº = - 27,500 J

∆Gº = -nFEº

∆Gº = -27.5 kJ

F = 96,485 C/mol e-

n = moles of e- = 1

Eºcell = -27500 / (-1)(96485) = 0.285 V