In basic solution, Se2− and SO3
2− ions react spontaneously:
2Se2−(aq) + 2SO3
2−(aq) + 3H2O(l) ⟶
2Se(s) + 6OH−(aq) + S2O3
2−(aq) E°
cell = 0.35 V
(a) Write balanced half-reactions for the process.
(b) If E°sulfite is −0.57 V, calculate E°selenium.
The answer is provided in the image below
=-0.92V
Comments
Leave a comment