Question #267204

10.0 g H2O reacts with 4.5 g Na to produce NaOH and H2. Identify the limiting reactant. *




1
Expert's answer
2021-11-17T16:14:01-0500

2Na+2H2O2NaOH+H22Na+2H_2O\to 2NaOH+H_2

moles of sodium=4.5/23=0.1957moles4.5/23=0.1957moles

moles of water = 10/18=0.5556moles10/18=0.5556moles

Moles of sodium are less than moles of water hence it is the limiting reactant.


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