Answer to Question #266385 in General Chemistry for papi

Question

The specific heat of aluminum is 0.902

J/g

·

o

C

. How much heat is absorbed

by an aluminum

pie tin with a mass of 473 g to raise its temperature

from room temperature (23.00

o

C

) to

oven temperature (375

o

F)?

Answer 1

$375^oF =(375-32)×(\frac{5}{9})^oC =190.5^oC$

Increase in temperature $=190.5-23 =167.5$

Required Heat= $0.902×167.5×473 J =71463.205 J$