Answer to Question #265386 in General Chemistry for elle

Question

When 0.935g of a fuel underwent complete combustion in excess oxygen, the increase of temperature of water in a calorimeter containing 1,365g of water was 2.40˚C. Calculate the higher calorific vale of the fuel, if the water equivalent of calorimeter, etc. is 135g.

Answer 1

Heat absorbed by water $=1365×2.4=3276cal$

Heat absorbed by Calorimeter$=135×2.4=324cal$

Total heat $=3276+324$

$=3600cal$

Higher Calorific value

$\frac{3600}{0.935}=3850cal/g$