When 0.935g of a fuel underwent complete combustion in excess oxygen, the increase of temperature of water in a calorimeter containing 1,365g of water was 2.40˚C. Calculate the higher calorific vale of the fuel, if the water equivalent of calorimeter, etc. is 135g.
Heat absorbed by water "=1365\u00d72.4=3276cal"
Heat absorbed by Calorimeter"=135\u00d72.4=324cal"
Total heat "=3276+324"
"=3600cal"
Higher Calorific value
"\\frac{3600}{0.935}=3850cal\/g"
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