The freezing point of pure camphor is 178.4°C, and its molal bpt contant, Kf, is 40°C. kg/mol. Find the freezing point of a solution containing 1.50 g of a compound of molar mass 125 in 35 g of camphor.
∆Tf= Kf×m×i
178×125/35×40= 15.89
15.89×1.5= 23.84°C
Comments
Leave a comment