Question

What is the specific heat in J/gC for a metal sample with a mass of 95.6 g which absorbs 841 J of energy when its temperature increases from 30.0 C to 98.0 C.

Answer 1

$∆T= 98.0-30.0=68.0°C$

$M=95.6g$ .

$Q=841J$

$C=M.C.∆T$

$C=95.6×841×68.0=5467172.8J/gC$