Question #264309

What is the specific heat in J/gC for a metal sample with a mass of 95.6 g which absorbs 841 J of energy when its temperature increases from 30.0 C to 98.0 C.


1
Expert's answer
2021-11-12T06:23:01-0500

T=98.030.0=68.0°C∆T= 98.0-30.0=68.0°C


M=95.6gM=95.6g .


Q=841JQ=841J


C=M.C.TC=M.C.∆T


C=95.6×841×68.0=5467172.8J/gCC=95.6×841×68.0=5467172.8J/gC



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