Answer to Question #264147 in General Chemistry for Eunice

Question

If 33 grams of iron (II) chloride reacts with 56 grams of sodium phosphate, what is the limiting reagent? How much sodium chloride can be formed? write your answer in one decimal place

example, 18.5 g of sample.

Answer 1

Balanced Equation

3FeCl₂+2Na₃PO₄$\implies$ Fe₃(PO₄)₂+6NaCl

Limiting reagent is FeCl₂

Moles of FeCl₂ =$\frac{33g}{126.751g/mol}$

=0.2604moles

Mole ratio of:

FeCl₂:NaCl

3 : 6

If 3=0.2604moles

$\therefore$ 6=?

$\frac{6×0.2604}{3}$ $=0.5208moles$

Molar mass of NaCl is 58.44g/mol

But Mass= 0.5208moles×58.44g/mol

=30.4g

Mass Of Sodium Chloride formed =30.4g