Answer to Question #264079 in General Chemistry for Mark

Question

How much thermal energy is required to heat all of the water in a swimming pool by 1°C if the dimensions are 4 ft deep

by 20 ft wide by 75 ft long? Report your result in megajoules.

Answer 1

$1ft=0.3048m$

volume of water in the pool $=(75\times 0.3048)(20\times 0.3048)(4\times 0.3048)=169.90m^3$

Density of water $=1000kg/m^3$

Mass of water $=169.90\times 1000$

Heat energy $=mc \Delta T = (169.90\times 1000)\times 4200\times 1=713.58 \times 10^6J=713.58MJ$