A mixture of 0.100 mol of NO,
0.050 mol of H2 and 0.10 mol
of H2O
is placed in a 1.0-L vessel at 300 K. The following equilibrium is established: 2 NO(g) + 2 H2(g)
N2(g) + 2 H2O(g). At
equilibrium [NO]
= 0.062 M. Calculate the
equilibrium concentrations of
H2, N2 and
H2O and Kc.
The answer is in the image
Comments
Leave a comment