Question

What is the solubility of NH₃ if it’s partial pressure is reduced to 220.0 mmgHg at 25 C

Answer 1

$s =\frac{ m N H 3}{ V}$

$\frac{51.8 g}{ 100 m l} = \frac{m N H 3}{ 2 , 500} m$

$m N H 3 = \frac{51.8}{ g 100} m l × 2 , 500 m l$

mNH3=1,295 g