What is the solubility of NH3 if it’s partial pressure is reduced to 220.0 mmgHg at 25 C
"s\n=\\frac{\nm\nN\nH\n3}{\nV}"
"\\frac{51.8\n \ng}{\n100\n \nm\nl}\n=\n\\frac{m\nN\nH\n3}{\n2\n,\n500}\n \nm"
"m\nN\nH\n3\n=\n\\frac{51.8}{\n \ng\n100}\n \nm\nl\n\u00d7\n2\n,\n500\n \nm\nl"
mNH3=1,295 g
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