How many grams of oxygen gas will completely react with 3.8 moles of propane
C3H8+5O2−−−>3CO2+4H2OC3H8 + 5O2 ---> 3CO2 + 4H2OC3H8+5O2−−−>3CO2+4H2O
Mole ratio CH3H8:O2= 1:5
= 5×3= 15moles of O2
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