Answer to Question #261074 in General Chemistry for Camille Basilio

Question

A piece of copper metal of mass 6.5kg is heated from 20.5°C to 324.3°C calculate the heat absorbed in kilo calories by the metal specific heat capacity of CU is 0.385 j/g°C

Answer 1

$\Delta\>H=mc\Delta\>T$

$6.5kg=6.5×1000=6500g$

$\Delta\>T=324.3-20.5=303.8°C$

$\Delta\>H=6500×0.385×303.8$

$=760259.5 \>Joules$

$1kilocalorie=4184Joules$

$Heat\> absorbed= \frac{760259.5}{4184}$

$=181.7 \>kilocalories$