A piece of copper metal of mass 6.5kg is heated from 20.5°C to 324.3°C calculate the heat absorbed in kilo calories by the metal specific heat capacity of CU is 0.385 j/g°C
Δ H=mcΔ T\Delta\>H=mc\Delta\>TΔH=mcΔT
6.5kg=6.5×1000=6500g6.5kg=6.5×1000=6500g6.5kg=6.5×1000=6500g
Δ T=324.3−20.5=303.8°C\Delta\>T=324.3-20.5=303.8°CΔT=324.3−20.5=303.8°C
Δ H=6500×0.385×303.8\Delta\>H=6500×0.385×303.8ΔH=6500×0.385×303.8
=760259.5 Joules=760259.5 \>Joules=760259.5Joules
1kilocalorie=4184Joules1kilocalorie=4184Joules1kilocalorie=4184Joules
Heat absorbed=760259.54184Heat\> absorbed= \frac{760259.5}{4184}Heatabsorbed=4184760259.5
=181.7 kilocalories=181.7 \>kilocalories=181.7kilocalories
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