Answer to Question #260631 in General Chemistry for Eerah Anitha

Question

A solution of benzene and toluene was prepared by adding toluene to benzene until the total volume becomes 135mL. By volume, the solution is 30.0% benzene. How much benzene, in mL, is in the solution?

Answer 1

Solve for the volume of benzene.

%V benzene = (V benzene / V solution) × 100

V benzene = (%V benzene)(V solution) / 100

V benzene = (30.0)(135 m L) / 100

V benzene = 40.5 m L