Question

What volume (in mL) of 0.0125 M HBr solution is required to titrate 250 mL of a 0.0100 M Ca(OH)₂ solution?

Ca(OH)₂ (aq) + 2 HBr (aq) → CaBr₂ (aq) + 2 H₂O (l)

Answer 1

Moles of $Ca(OH)_2=0.0100×\frac{250}{1000}=0.0025moles$

Moles of $HBr=0.0025×2=0.0050moles$

Volume $= \frac{0.0050}{0.0125}=0.4L = 400ml$