Calculate the formula mass of(a.m.u) of the AL2o3
=26.9815×2+15.9994×3=53.963+47.9982=101.9612 a.m.u.= 26.9815 \times 2 + 15.9994 \times 3 \\ = 53.963 + 47.9982 \\ = 101.9612 \; a.m.u.=26.9815×2+15.9994×3=53.963+47.9982=101.9612a.m.u.
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