Answer to Question #259337 in General Chemistry for temmy

Question

Calculate the change in enthalpy of the given reaction using Hess' Law

Given the following enthalpy changes:

H2 + 1/2 O2 -> H2O ΔH= -286kJ

CO2 -> C + O2 ΔH= +394 kJ

2 CO2 + H2O -> C2H2 + 5/2 O2 ΔH= +1300 kJ

Calculate the ΔH for the following reaction:

C2H2 -> 2C + H2

Answer 1

H₂O$\to$ H₂+1/2O₂ $\Delta$ H=+286kJ

2CO₂$\to$ 2C+2O₂ $\Delta$ H=2(394)kJ

C₂H₂ + 5/2 O₂ $\to$2 CO2 + H2O  ΔH= -1300 kJ

ΔH=286+2(394)+(-1300)

=-226kJ