Answer to Question #258368 in General Chemistry for bigdawg

Question

QUESTION 11. In a 6.00 L pressure cooker, water is brought to a boil. If the final temperature is 115 °C at 3.95 bar, how many moles of steam are in the cooker? (R = 0.08314 L･bar/mol･K)

Answer 1

PV= nRT

$3.95×6=n(0.08314×[115+273])$

$n=\frac{23.7}{32.25832}=0.73moles$