Answer to Question #258211 in General Chemistry for Meg

Question

what is the free energy change for the reaction SiO(s)+Pb(s) -> PbO2(s)+Si(s)?

deltaGf(PbO2)= -217 kj/mol

deltaGf(SiO2)= -856 kj/mol

Answer 1

deltaG = deltaGf(product) - deltaGf(reactants)

= (deltaGfPbO₂ + deltaGfSi) - (deltaGfSiO₂ + deltaGfPb)

= (-217 + 0) - (-856 + 0)

= -217 + 856

= 639kJmol^-1