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Answer to Question #258097 in General Chemistry for taerah
Question #258097
An arrow is shot at an angle of 85º from the horizontal with an initial velocity of 15m/s.
a.What is its velocity after 9.5 s?
Expert's answer
V=U2-2gh
V= (15sin80)2-2×9.5×h
V=182.25-19h
0=182.25-19h
182.25=19h
=9.61m/s
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