Answer to Question #258095 in General Chemistry for taerah

Question

1. An object moving in a straight line at 15 m/s is under constant acceleration. After 5.0 s, its velocity is 17.5 m/s.

a.How far did the object travel this time?

b.What is the acceleration of the object?

Answer 1

at t = 0.0s, v = u = 15m/s

at t = 5.0s, v = 17.5m/s

a.

$s = (\dfrac{u+v}2)t= (\dfrac{15+17.5}2)×5\\ s =16.25×5 = 81.25m$

b.

$v = u+at \\ 17.5 =15+ a(5)\\ 2.5 = 5a\\ a = 0.5m/s²$