Question

80.0 grams of glucose (C6H12O6, mol. wt = 180. g/mol) is dissolved in enough water to make 1.00 L of solution. What is its molarity?

Answer 1

Moles $=\frac{80}{180}=0.4$

Molarity $=\frac{0.4}{1.00}=0.4 molarity$