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Answer to Question #256768 in General Chemistry for Syu
Question #256768
The experiment is repeated with 1.0 M ethanoic acid to replace the sulphuric
acid. Calculate the volume of ethanoic acid, CH3COOH needed to neutralize 25mL of
potassium hydroxide solution
Expert's answer
Molar mass of ethanoic acid = 60.052 g/Mol
Molar mass of KOH =56.1056
25/56.1056= 0.446mol
0.446×60.052= 26.76ml of CH3COOH
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