Ammonium nitrate (NH₄NO₃), an important fertilizer, produces dinitrogen oxide (N₂O) gas and H₂O when it decomposes. Determine the mass of H₂O produced from the decomposition of 25.0 grams of solid NH₄NO₃. Reaction: NH₄NO₃ -> N₂O + 2 H₂O
M(NH4NO3) = 80.04 g/mol
m(NH4NO3) "= \\frac{25.0}{80.04} = 0.312 \\;mol"
According to the reaction:
n(H2O) = 2n(NH4NO3) "= 2 \\times 0.312 = 0.624 \\;mol"
M(H2O) = 18.01 g/mol
m(H2O) "= 0.624 \\times 18.01 = 11.25 \\;g"
Answer: 11.25 g
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