Question

A 50.0 mL sample of HNO₃ is neutralized by reaction with 120.0 mL of 2.50 M NaOH. What is the concentration of HNO₃ is the unknown sample?

Answer 1

NaOH (aq) + HNO₃ (aq) → NaNO₃ (aq) + H₂O (l)

Moles of $NaOH =\frac{2.50×120}{1000}=0.3moles$

Molarity of $HNO_3=\frac{0.3×1000}{50}=6M$