Question

1. At what temperature will a solution that is composed of 0.73 moles of glucose (C6H12O6) in 650mL of water (H2O) begin to boil?

Answer 1

Using the relation ΔTb​=mKb

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Molarity $=\frac{0.73×1000}{650}=1.123M$

Hence, $ΔTb=1.123×0.52=0.58K$

Hence, the boiling point of the solution will increase by 0.58 K

New boiling point $=373.15+0.58=373.73 k$