Answer to Question #254917 in General Chemistry for bensu

Question

An aluminum cylinder is 10.0 cm in length and has a radius of 0.25 cm. If the mass of a single Al atom is 4.48 × 10−23g, calculate the number of Al atoms present in the cylinder. The density of aluminum is 2.70 g/cm3 .

Answer 1

V=πr²h=π·0.25²·10≈1.9635cm³

Mass of Aluminum =1.9635×2.7=5.3036g

No. of aluminum atoms in the cylinder

=5.3036/4.48×10^-23

=1.1838×10²³ Al atoms