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Answer to Question #254898 in General Chemistry for bensu
Question #254898
Q 3.27 Calculate the number of C, H, and O atoms in 1.50 g of glucose (C6H12O6), a sugar.
Expert's answer
v(c6h12o6)=1.5/180=0.008mol
m(C)=6*0.008*12=0.6g
m(H)=12*0.008*1=0.1g
m(O)=6*0.008*16=0.8g
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