Answer to Question #254870 in General Chemistry for hebba

Question

B₂H₆ + 3 O₂ → 2 HBO₂ + 2 H₂O What mass of O₂ will be needed to burn 3.3 mol of B₂H₆? MM( O2) = 32 g/mol 

Answer 1

According to the reaction:

n(O₂) = 3n(B₂H₆) $= 3 \times 3.3 = 9.9 \;mol$

m(O₂) $= 9.9 \times 32 = 316.8 \;g$

Answer: 316.8 g