B₂H₆ + 3 O₂ → 2 HBO₂ + 2 H₂O What mass of O₂ will be needed to burn 3.3 mol of B₂H₆? MM( O2) = 32 g/mol
According to the reaction:
n(O2) = 3n(B2H6) "= 3 \\times 3.3 = 9.9 \\;mol"
m(O2) "= 9.9 \\times 32 = 316.8 \\;g"
Answer: 316.8 g
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