Calculate the volume of acid needed to prepare 500ml of 2.0 molar concentration of acid,if the stock bottle of the acid reads 1.25 specific gravity, 56% by mass and molar mass of acid 56.
To calculate the molarity of a solution that is 56% by mass, begin by calculating the total mass of one L of the solution. Given that the specific gravity of the solution is 1.25, we know that one L of the solution weighs 1250g. Multiplying the total weight by the percentage we get the number of grams of acid per liter.
"56.0 \\% \\times 1250 \\;g\/L = 700 \\;g\/L"
Then divide by the molecular weight to obtain the molarity.
"Molarity = 700 \\;g\/L \\times \\frac{1\\;mol}{56 \\;g} = 12.5 \\;M"
500 ml of 2.0 M solution will contain 1 mol of acid.
Proportion:
12.5 mol – 1000 mL
1 mol – x
"x = \\frac{1 \\times 1000}{12.5} = 80 \\;mL"
Answer: 80 mL
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