Answer to Question #254122 in General Chemistry for lei

Question

1.   Calculate the [OH^-] and pH of each of the following strong base solutions:

 a.   0.0050 M KOH

b.   2.055 g of KOH in 500.0 mL of solution

c.    1.00 mL of 0.175 M NaOH diluted to 2.00 L.

 

Answer 1

We are given 0.0050 M KOH solution:

KOH is a strong base, so it dissociates in the solution 100% as follows:

KOH→K⁺+OH^-

The concentration of hydroxide ion is equal to the that of KOH because 1 mole of KOH releases 1 mole of hydroxide ion.

[OH^-]=0.0050M

pOH= -log(OH^-)

= -log0.005

pOH= 2.3

pH= 14-2.3= 11.3