Answer to Question #253342 in General Chemistry for Jhosie

Question

CO was allowed to react with Fe2O3 in the amount of 43.95grams.what is the amount of Fe that will be created because of the reaction?

Answer 1

The mass of iron oxide which reacts with 36.03 g of carbon = 159.69 g

The mass of iron oxide which reacts with 8.320 g of carbon= (159.69 x8.320) / 32.03 = 41.48 g

2.

2Na + Cl_2 \to 2NaCl

According to the chemical equation written above

2 moles of Na (23 x 2 = 46 g ) reacts with amount of chlorine = 1 mol (70.9 g)

7.589 g of Na reacts with amount of chlorine = (70.9 x 7.589) / 46 = 11.697 g

Given mass of chlorine = 30.54 g

Na is limiting reagent as it will decide the yield of the reaction products.

and Cl2 is excess reagent.

Now , theoretical yield of NaCl can be calculated as :

46 g of sodium reacts with chlorine to give = 58.44 g of NaCl

7.589 g of Na reacts with chlorine and will give = (58.44 x 7.589) / 46 =9.641 g

Theoretical yield = 9.641 g

Excess reagent used = 11.697 g

Excess reagent leftover= 30.540 g - 11.697 g =`8.843 g

Actual yield = 1.635 g

Yield % =( Actual yield x 100) / theoretical yield = (1.635 x 100) / 9.641 = 16.95 %