H3PO4 + 3KOH → K3PO4 + 3H2O
M(H3PO4) = 98.0 g/mol
n(H3PO4) "= \\frac{49.0}{98.0}= 0.5 \\;mol"
According to the reaction:
n(H3PO4)=n(K3PO4) = 0.5 mol
M(K3PO4) = 212.0 g/mol
m(K3PO4) "= 0.5 \\times 212.0 = 106.0 \\;g"
Proportion:
106.0 g – 100 %
49.0 g – x
"x = \\frac{49.0 \\times 100}{106.0} = 46.22 \\; \\%"
Answer: 46.22 %
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