A 0.810 kg of H2O vapor is contained in a vessel with a volume of 655 liters at 150.5°C. Calculate the pressure (in mmHg) of the water vapor inside the vessel.
Molar mass of H2O = 18.01528 g/mol
810/18.01528= 44.962moles
PV= nRT
P655= 44.962× 8.314 J/mol·K.×423.5
P655= 158310.26
P= 241.7mmHg
Comments
Leave a comment