Answer to Question #252525 in General Chemistry for Larah

Question #252525
Determine how many mL of 0.102M NaOH solution are needed to neutralize 35.0 mL of 0.125M H2SO4 solution. Show the given, balanced equation, solution and final answer.
1
Expert's answer
2021-10-18T04:51:35-0400

2NaOH+H2SO4→2H2O+2Na+SO4


moles of sulfuric acid = (0.035 L)(0.125 M) =0.0044mol

0.0044× 2× 0.102

= 0.0008976mol

39.997 × 0.0008976= 0.036


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