Determine how many mL of 0.102M NaOH solution are needed to neutralize 35.0 mL of 0.125M H2SO4 solution. Show the given, balanced equation, solution and final answer.
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Expert's answer
2021-10-18T04:51:35-0400
2NaOH+H2SO4→2H2O+2Na+SO4
moles of sulfuric acid = (0.035 L)(0.125 M) =0.0044mol
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