Answer to Question #252222 in General Chemistry for Larah

Question #252222
The molarity of a hydrochloric acid solution can be determined by titrating a known volume of solution with a sodium hydroxide solution of known concentration. If 14.7 mL of 0.102 M NaOH is required to titrate 25.00 mL of a hydrochloric acid, HCl, solution , what is the molarity of the hydrochloric acid?
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Expert's answer
2021-10-17T11:25:32-0400

NaOH (aq) + HCl (aq) → NaCl (aq) + H2O (l)


Mole ratio 1:1


Moles of NaoH=0.102×14.71000=0.0015=0.102×\frac{14.7}{1000}=0.0015


Molarity of HCL=0.001525×1000=0.06M=\frac{0.0015}{25}×1000=0.06M




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