Question

The molarity of a hydrochloric acid solution can be determined by titrating a known volume of solution with a sodium hydroxide solution of known concentration. If 14.7 mL of 0.102 M NaOH is required to titrate 25.00 mL of a hydrochloric acid, HCl, solution , what is the molarity of the hydrochloric acid?

Answer 1

NaOH (aq) + HCl (aq) → NaCl (aq) + H₂O (l)

Mole ratio 1:1

Moles of NaoH$=0.102×\frac{14.7}{1000}=0.0015$

Molarity of HCL$=\frac{0.0015}{25}×1000=0.06M$