The molarity of a hydrochloric acid solution can be determined by titrating a known volume of solution with a sodium hydroxide solution of known concentration. If 14.7 mL of 0.102 M NaOH is required to titrate 25.00 mL of a hydrochloric acid, HCl, solution , what is the molarity of the hydrochloric acid?
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Expert's answer
2021-10-17T11:25:32-0400
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
Mole ratio 1:1
Moles of NaoH"=0.102\u00d7\\frac{14.7}{1000}=0.0015"
Molarity of HCL"=\\frac{0.0015}{25}\u00d71000=0.06M"
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