K=ln2t12=0.69313.1=5.29×10−2hr−1K=\frac{ln2}{t_{\frac{1}{2}}}=\frac{0.693}{13.1}=5.29×10^{-2}hr^{-1}K=t21ln2=13.10.693=5.29×10−2hr−1
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