The freezing point depression
"\u0394T_f =k_fm \\\\\n\nk_f = 1.86 \\;\u00b0C\/m"
Molality
"m = \\frac{Number \\;of \\;moles\\; of\\; glucose}{Weight \\;of \\;solvent\\; in\\; kg}"
M(glucose) = 180 g/mol
Molality
"n(glucose) =\\frac{10.3}{180} = 0.05722 \\\\\n\nm= \\frac{0.05722}{250 \\times 10^{-3}} = 0.2288 \\;m \\\\\n\n\u0394T_f =1.86 \\times 0.2288 = 0.425 \\;\u00b0C"
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