Question

 Given the same reactant concentrations, the reaction CO (g) + CI₂ (g) —> COCI₂ (g)

at 250°C is 1.50x10^3 times as fast as the same reaction at 150°C. Calculate the activation energy for this reaction. Assume that the frequency factor is constant.

Answer 1

Ea/R x (1/T1 - 1/T2)

= 1.5×10³×(1/523-1/473)

= 0.0019-0.002

= -0.0001

1.5×10³×-0.001

= 1.5J/mol