2 C2H6(g) + 2 O2(g) = CO2(g) + 2 H2O(I)
1. How many grams of H2O will be produced by 58.2 L of CH4 at STP? Assume an excess of O2.
Molar mass of CH4= 16.04 g/mol
58.2/22.4= 2.598moles
Molar mass of H2O= 18.01528 g/mol
Mole ratio 2:2
= 2.598×18.01528= 46.81g
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