Question

Calculate the number of Li+ ions in 8.12g Li3PO4

Answer 1

Since lithium orthophosphate contains 3 lithium ions, the amount of lithium ion substance will be equal to:

$n(Li3PO4) = \frac{9.18}{115.79} = 0.06 \ mole$

$n(Li^+) = n(Li3PO4) \times 3 = 0.18 \ mole$