Calculate the number of Li+ ions in 8.12g Li3PO4
Since lithium orthophosphate contains 3 lithium ions, the amount of lithium ion substance will be equal to:
"n(Li3PO4) = \\frac{9.18}{115.79} = 0.06 \\ mole"
"n(Li^+) = n(Li3PO4) \\times 3 = 0.18 \\ mole"
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