∆H"^{\\theta}{_c}=-41.6kJmol^{-1}"
"=-41600Jmol^{-1}"
Number of moles that releases 28.15J of heat
"=\\frac{28.15}{41600} moles"
Therefore "\\frac{28.15}{41600} moles" is equivalent to
0.0167g
Molar mass "=0.0167\u00f7(\\frac{28.15}{41600})"
"=0.0167\u00d7\\frac{41600}{28.15}"
= 24.6792g
Comments
Thanks for answering ☺️
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