Answer to Question #251200 in General Chemistry for Maykyllah Jane

Question #251200
When 0.0167 g of a compound with a heat of combustion of -41.6 kJ/mole is burned
in a calorimeter, 28.15 J of heat is released. What is the molar mass of the compound?
1
Expert's answer
2021-10-15T02:58:47-0400

∆Hθc=41.6kJmol1^{\theta}{_c}=-41.6kJmol^{-1}

=41600Jmol1=-41600Jmol^{-1}

Number of moles that releases 28.15J of heat

=28.1541600moles=\frac{28.15}{41600} moles


Therefore 28.1541600moles\frac{28.15}{41600} moles is equivalent to


0.0167g


Molar mass =0.0167÷(28.1541600)=0.0167÷(\frac{28.15}{41600})


=0.0167×4160028.15=0.0167×\frac{41600}{28.15}


= 24.6792g

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Comments

Mikay
15.10.21, 10:24

Thanks for answering ☺️

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