Answer to Question #251183 in General Chemistry for Yuu

Question

Calculate the mass of manganese (IV) oxide that can be synthesized from 15.00 grams of potassium iodide.

Answer 1

6KI_(aq) +4H₂O_(l)+2KMnO_4(aq)$\to$ 3l_2(s) +2 MnO_2(s)+8KOH_(aq)

REM of KI=166.00 g/mol

Moles of KI=15/ 166

= 0.09036moles

Mole ratio= KI:MnO₂ = 6:2 = 3:1

Moles of MnO₂= 0.09036/3

=0.03012moles

REM of MnO₂= 86.99 g/mol

Mass of MnO₂= 0.03012× 86.97

=2.6195364g