A hundred grams of sulfuric acid yielded ten grams of water.
Balanced
H2SO4(l) = H2O(l) + SO3(l)
Moles of H2SO4 = "\\frac{100}{98}=1.02 moles"
Moles of H2O "=1.02 moles"
Not applicable for limiting and excess reactant
Theoretical yield = 1.02 × 18=18.36 g
Percent yield = "\\frac{18}{18.36}\u00d7100=98" %
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