Question

A hundred grams of sulfuric acid yielded ten grams of water.

Answer 1

Balanced

H2SO4(l) = H2O(l) + SO3(l)

Moles of H2SO4 = $\frac{100}{98}=1.02 moles$

Moles of H2O $=1.02 moles$

Not applicable for limiting and excess reactant

Theoretical yield = 1.02 × 18=18.36 g

Percent yield = $\frac{18}{18.36}×100=98$ %