Answer to Question #250920 in General Chemistry for MAY

Question

A gas sample with a volume of 525 mL and temperature of -25.0 °C is heated to 175.5 °C.

What is the new volume of the gas if pressure and number of moles are held constant?

Answer 1

$V_1 = 525 \;mL \\ T_1= -25.0 \;°C = 248 \;K \\ T_2 = 175.5 \;°C = 448.5 \;K \\ P= constant \\ \frac{V_1}{T_1} = \frac{V_2}{T_2} \\ V_2 = \frac{V_1 \times T_2}{T_1} \\ = \frac{525 \times 448.5}{248} = 949.44 \;mL$

Answer: 949.44 mL